** Company: ** i2 Technologies

Q1.Convert 0.9375 to binary

a) 0.0111

b) 0.1011

c) 0.1111

d) none

Ans. (c)

Q2.( 1a00 * 10b )/ 1010 = 100

a) a=0, b=0

b)a=0, b=1

c) none

Ans. (b)

Q3. In 32 bit memory machine 24 bits for mantissa and 8 bits for exponent. To increase the range of floating point.

a) more than 32 bit is to be there.

b) increase 1 bit for mantissa and decrease 1 bit for exponent

c) increase 1 bit for exponent and decrease one bit for mantissa

Q4.In C, “X ? Y : Z ” is equal to

a) if (X==0) Y ;else Z

b) if (X!=0) Y ;else Z

c) if (X==0) Y ; Z

Ans. (b)

Q5. From the following program

foo()

int foo(int a, int b)

{

if (a&b) return 1;

return 0;

}

a) if either a or b are zero returns always 0

b) if both a & b are non zero returns always 1

c) if both a and b are negative returns 0

Q6. The following function gives some error. What changes have to be made

void ( int a,int b)

{

int t; t=a; a=b; b=t;

}

a) define void as int and write return t

b) change everywhere a to *a and b to *b

Q7. Which of the following is incorrect

a) if a and b are defined as int arrays then (a==b) can never be true

b) parameters are passed to functions only by values

c) defining functions in nested loops

Q8. include

void swap(int*,int*);

main()

{

int arr[8]={36,8,97,0,161,164,3,9}

for (int i=0; i<7; i++) { for (int j=i+1; j<8;j++) if(arr[i]<arr[j]) swap(&arr[i],&arr[j]);=”” }=”” void=”” swap(int*x,int*y)=”” {=”” int=”” temp;=”” static=”” cnt=”0;” temp=”*x;” *x=”*y;” *y=”temp;” cnt++;=”” what=”” is=”” equal=”” to=”” a)=”” 7=”” b)=”” 15=”” c)=”” 1=”” d)=”” none=”” of=”” these=”” q9.=”” main()=”” file=”” *fp;=”” fp=”fopen(“test.dat”,”w”);” fprintf(fp,’hellon”);=”” fclose(fp);=”” (“test.dat”,”w”);=”” fprintf=”” (fp,=”” “world”);=”” return=”” 0;=”” if=”” text.dat=”” already=”” present=”” after=”” compiling=”” and=”” execution=”” how=”” many=”” bytes=”” does=”” the=”” occupy=”” ?=”” 0=”” 5=”” 11=”” data=”” insufficient=”” q10.=”” f1(int*x,intflag)=”” *y;=”” switch(flag)=”” case=”” 0:=”” break;=”” 1:=”” 2:=”” return(*y)=”” i=”f1(x,0);” j=”f1(x,1);” printf(“%d=”” %d=”” “,i,j,*x);=”” output?=”” 8=”” <=”” p=””></arr[j])>

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