Aptitude

1.How many 2 digit numbers are there which have 8 as the unit number in it’s square.
(a)3
(b)None
(c)2
(d)1

2. B is 8km East of A. C is 6km North of B. D is 12km East of C. E is 16km North of D. What is the distance b/w A and E.
(a)20km
(b)22km
(c)18km
(d)30km

3. x+y = z
Then
(a)…
(b)y

4.Two people were walking in opposite directions. both of them walked 6 miles forward then took right and walked 8 miles. how far is each from starting positions?
a) 14 miles and 14 miles
b) 10 miles 10 miles
c) 6 miles 6 miles

5 A person has certain number of cows and birds. they have 172 eyes and 344 legs. how many cows and birds does he have?

6 A person has 14 red socks and 14 white socks in a drawer. what is the minimum number of socks that he should take to get a correct pair?

7.When a number is multiplied by 13,it will become greater to 105 by an amt with which it is lesser to105 by now. what is the number

8. When asked what the time is, a person answered that the amount of time left is 1/5 of the time already completed. what is the time?

9.When I become as old as my father is now, I will be 5 times the age of my son. and my son will be 8 yrs older than what I am now.father+my age=100.how old is my son now?

10. Two peoples on cycles are traveling at 10 miles / hour. when they reach a distance of 50 miles, a housefly lands on the first cyclist and then flies to the other and so on…at a speed of 16 miles/hour. what is the distance covered by fly before cyclist meet?

11..My successor’s father is my father’s son. and I don’t have any brothers or sons. who is my successor?
a)nephew
b)niece
c)daughter
d)myself

12.The hours remaining in a day is one-fifth of the hours passed in the day. What is the time?

13. My successor is my uncles only brothers son who is his only kid.

14.A and B starts from the same point and moves in opposite direction for 8 miles and 6 miles respectively. After that A turns right and moves for another 6 miles. B also turns right and moves 8
miles. What are their respective distance from the starting point? 10,10

15 In a pet shop there are 120 eyes and 172 legs. How many birds and puppies are included in these?

16 Two cyclists are moving towards each other at 10 miles/hour. They are now 50 miles apart. At this instance a fly starts from one cyclist and move towards other and moves to and fro till the two
cyclist meet each other. If the fly is moving at 15 miles/hour, what is the total distance covered by the fly? 50 80 100 6. Guru s draw has 14 blue socks and 14 black socks. How many socks must be taken to get a pair of socks of the same color? 14 15 13 16

COMPUTER SCIENCE

1. which of these checks for structural errors of a language
a)lexical analyser
b)parser
c)intermediate code
d)code optimisation

2. threads in the same process share the same
a)data section
b)stack
c)registers

3.the depth of a binary tree…
a)nlogn(base 2)
b) n*n
c)n

4.a program computing log(n) accepts 1000 inputs its execution time is 110 ms…when it doubles n to 2000 inputs..it becomes 120…..and what will be for 4000
a)130
b)140
c)150

5.algorithm to find the balancing of paranthesis was given and output had to be obtaines…using stacks…easy yaar….

6.which of the followin is non preemptive
fcfs
round robin
shortest job first

7.problem to find the avg waitin time of sjf..given the burst times of each process

8.which of the follwing may be implemented using a stack
parenthesis matchin
parsing
local variables stored in runtime
all the above

9.which of the foll data structures can be randomly accessed givin loc
4.both single and double linked list

C SECTION

1. Find output ………….
Int *ptr=&const;
((((( ans:error)))))

2. Find output Function(i=10);
(((((ans:error)))))

3. #define SWAP(x,y) t=x;x=y;y=t;
main()
{ int x=5,y=6;
if (x>y)
SWAP(x,y);
Printf( x=%d y=%dn ,x,y);
} ((( note that the function SWAPis not within braces))))

4. sum(int x)
{int t;
printf(“%d”,i);
}
Ans: 0

4.
What is the output of the Program?
main()
{
int a[10];
3[a]=10;
printf(“%d”,*(a+3));
}
Ans: 10

5.
int (*p[10]) ();
In above declaration what type of variable is P?
Ans: P is array of pointers that each points to a function that takes no arguments and returns
an int.

6.
What is the output of the Program?
struct emp
{
int a=25;
char b[20]=”tgk”;
};
main
{
emp e;
e.a=2;
strcpy(e.b,”tellapalli”);
printf(“%d %s”,e.a,e.b);
}
Ans: Compile Error.

7.
What is the output of the Program?
main()
{
int a=5;
const int *p=&a;
*p=200;
printf(“%d”,*p);
}Ans: Compile Error.

8.
What is the output of the Program?
#define SQ(x) x*x
main()
{
int a=SQ(2+1);
printf(“%d”,a);
}
Ans: 5.

9.
What is the output of the Program?
main()
{
struct t
{
int i;
} a,*p=&a;
p->i=10;
printf(“%d”,(*p).i);
}
Ans: 10

10.
This program will be Compiled? [Yes/No]
zzz.c file
———-
/* This is zzz.c file*/
/*printf(“tellapalli”);*/
abc.c file
———-
main()
{
#include”zzz.c”
printf(“Tellapalli”);
}
Ans: Yes

COMP SC.
1. IN BINARY TREE IF PARENT HAS INDEX i then its left and right child
occurs at:
ans (a) 2i and 2i+1

2. 1 prog is given n scope is asked
ans (b) static scope (probably)

3. complete graph has
ans (b) n vertices and n(n-1)/2 edges

4. page fault is said 2 occur when:

5. choices r given probably (c)

6. probability that a frame is recieved with an error is P in a system. probability that the first frame to b recieved with an error is after the first N frame is
(a) (1-P)*(p raised to power N)
(b) [(1-P) raised to power (N-1)]
(c) p raised to power N
(d) combination of N taken P at a time6. statistical time division multiplexing provides:
(a) statistics of tdm signal
(b) provision to multiplex analog signal
(c) improved time sharing efficiency
(d) static routing b/w nodes
ans (b) check

7. main advantage of AMI coding is
(a) easy clock recovery
(b) easy carrier recovery
(c) reduced bandwidth req
(d) reduced error rate

8. recursive-descent parser is a
(a) top-down parser
(b) bottom-up parser
(c) shift-reduce parser
(d) LR parser

9. min. no. of NAND gates reqd to implement a 2 i/p x-nor gate
(a) 2
(b) 3
(c) 4
(d) 5

10. mandatory feature of a real time OS is:
(a) priority based preemptive scheduling
(b) high time slicing granularity
(c) run to completion
(d) none of the above
These are the Queston asked in the sasken wirtten held on 19th at 3.00 p.m batch.
The Question paper is of three sections
i ) c (most of the questions) and c++;
ii) Apptitude (R.S agarwal)
iii)basic commputer

Each section has 10 questions and the way they aorganised was good and timely.
c and c++;

1. char buffer[]=”susan”;
a) individual characters can be changed.
b) buffer[7] is not accesible.
c)none of the above.
which of the above is TRUE;
ans : a)

2.#include
#include
void main()
{
int ctr=0;
clrscr();
switch(ctr)
{
case 0:
ctr++;
case 1:
ctr++;
default :
ctr++;
};
printf(“%d”,ctr);
getch();
}

What is the output of the code.
i) ctr=2;
ii) ctr=3;
iii) ctr=1;
iv) compiler error;
Ans : iii) 3.#include
#include
void main()
{
void fun(int,int);
int i ,j;
i=2,j=3;
fun(i++,j++);
printf(“%d%d”,i,j);
getch();
}
void fun(int i,int j)
{
i++,j++;
}
Question : what is the output ?
i)i=2,j=3;
ii)i=3,j=4;
iii)i=5,j=6;
iv) compiler error.
Ans : ii) 4)
#include
#include
void main()
{
int a[20];
clrscr();
*a=(int*)malloc(sizeof(a));
printf(“%d”,sizeof(a));
getch();
} 5)
#include
#include
void main()
{
char *s=”susan”;
clrscr();
printf(s);
getch();
}
i) compiler error;
ii) s;
iii) susan;
iv) 5;
Ans: iii)
6)
i) const * int p;
ii) int const *p;
iii) const int *p;

Question : which of the following is same.
a)i) and ii)
b)i),ii) and iii)
c)ii) and iii)
d)none of the above.
i) (*ptr)++;
ii) *ptr+=1;
iii) *ptr++;

Question: which of the folowing is same.
a)i) and ii)
b)i),ii) and iii)
c)ii) and iii)
d)none of the above.

a)for(int i=0; i<50 ;i++) for( int j=0; j<100; j++) a[i][j]=100; b)for(int i=0; i<100 ;i++) for( int j=0; j<50; j++) a[j][i]=100; Question : Which of the above 2 codes executes quickly. i) a) is faster than b) ii) b) is fater than a) iii) both a) and b) executes for same time. iv) depends upon the compiler and the hardware used. Ans: ” I think iii)” (check it out) fun( int x, int y) { x =3; y =2; } main() { int i; fun( i,i); printf(“%d”,i); } Question :if the value is 2 then the calling mechanism is a. Call by name b. Call by refernce c. Call by value ans : call by reference 1.Consider the following declaration:-char const *p = ‘d’; Which of the following is not a permissible operation (a) *p++ (b) ++p (c) (*p)++ (d) All 2.What is the output of the following code:- void print_arr(float **p) { printf(” 0 %f 1 %f 2 %fn”,p[0][0],p[0][1],p[0][2]); } void main() { float arr[2][3] = {{0,1,2},{3,4,5}}; float **fl_arr; fl_arr = (float *)arr; print_arr(fl_arr); fl_arr++; print_arr(fl_arr); } (a) (d)segmentation fault 3.What is the output of the following code:- #define putchar (c) printf(“%c”,c) void main() { char s=’c'; putchar (s); } (a) c (b) 99 (c) Compilation error (d) Execution error 4.What is the output of the following code:- void main() { printf(“%d”,printf(“ABC”)); } (a) ABC (b) 1 (c) ABC4 (d) ABC3 5.What is the output of the following code:- int compute(int n) { if(n>0)
{
n=compute(n-3)+compute(n-1);
return(n);
}
return(1);
}
void main()
{
printf(“%d”,compute(5));
}
(a) 6
(b) 9
(c) 12
(d) 13
6.What is the output of the following code:-
void main()
{
int i;
for(i=0;i<3;i++) { int i=100; i–; printf(“%d..”,i); } } (a0..1..2.. (b)99..98..97.. (c)100..100..100.. (d)99..99..99.. 7.What is the output of the following code:- void main() { int a[]={9,4,1,7,5}; int *p; p=&a[3]; printf(“%d”,p[-1]); } (a)6 (b)1 (c)7 (d)Error 8.What is the output of the following code:- void main() { int a[]={10,20,30,40,50}; int *p; p= (int*)((char *)a + sizeof(int)); printf(“%d”,*p); } (a)10 (b)20 (c)30 (d)40 9.Which code will run faster for(i=0;i<100;i++) for(j=0;j<10;j++) a[i][j]=0; OR for(j=0;j<10;j++) for(i=0;i<100;i++) a[i][j]=0; (a)First code (b)Second code (c)Same (d)Compiler and hardware dependent .Consider the following declaration:-char const *p = ‘d’; Which of the following is not a permissible operation (a) *p++ (b) ++p (c) (*p)++ (d) All 2.What is the output of the following code:- void print_arr(float **p) { printf(” 0 %f 1 %f 2 %fn”,p[0][0],p[0][1],p[0][2]); } void main() { float arr[2][3] = {{0,1,2},{3,4,5}}; float **fl_arr; fl_arr = (float *)arr; print_arr(fl_arr); fl_arr++; print_arr(fl_arr); } (a) (d)segmentation fault 3.What is the output of the following code:- #define putchar (c) printf(“%c”,c) void main() { char s=’c'; putchar (s); } (a) c (b) 99 (c) Compilation error (d) Execution error 4.What is the output of the following code:- void main() { printf(“%d”,printf(“ABC”)); } (a) ABC (b) 1 (c) ABC4 (d) ABC3 5.What is the output of the following code:- int compute(int n) { if(n>0)
{
n=compute(n-3)+compute(n-1);
return(n);
}
return(1);
}
void main()
{
printf(“%d”,compute(5));
}
(a) 6
(b) 9
(c) 12
(d) 13
6.What is the output of the following code:-
void main()
{
int i;
for(i=0;i<3;i++) { int i=100; i–; printf(“%d..”,i); } } (a0..1..2.. (b)99..98..97.. (c)100..100..100.. (d)99..99..99.. 7.What is the output of the following code:- void main() { int a[]={9,4,1,7,5}; int *p; p=&a[3]; printf(“%d”,p[-1]); } (a)6 (b)1 (c)7 (d)Error 8.What is the output of the following code:- void main() { int a[]={10,20,30,40,50}; int *p; p= (int*)((char *)a + sizeof(int)); printf(“%d”,*p); } (a)10 (b)20 (c)30 (d)40 9.Which code will run faster for(i=0;i<100;i++) for(j=0;j<10;j++) a[i][j]=0; OR for(j=0;j<10;j++) for(i=0;i<100;i++) a[i][j]=0; (a)First code (b)Second code (c)Same (d)Compiler and hardware dependent