A begins riding his bicycle at 10 am with a speed of 20kmph and B likewise begins at 10 am with a speed of 40kmph from a similar point in a similar way. Returns south at 12 o’clock and B turns north at 11 am. What will be the Distance between A and B at 2 pm? A) 250 km B) 160 km C) 170 km D) 145.6 km

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A begins riding his bicycle at 10 am with a speed of 20kmph and B likewise begins at 10 am with a speed of 40kmph from a similar point in a similar way. Returns south at 12 o’clock and B turns north at 11 am. What will be the Distance between A and B at 2 pm?

A) 250 km
B) 160 km
C) 170 km
D) 145.6 km

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Answer: B 160 km
Solution:
At 12 O’clock, A cover 40km and on the opposite side B at 11 o clock cover 40km, again they went towards each other (which is really the separation between them), that is A needs to make a trip 2hr (From 12 to 2 at 20km/hr.) i.e. 2*20=40km and opposite side B needs to Travelled out 3hr (From 11 to 2 at 40km/hr.) i.e. 3*40=120Km.
At that point Then the total distance traveled by them is the Actual distance between them i.e. 40+120= 160Km (Ans.)